2(x)=x^2+1

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Solution for 2(x)=x^2+1 equation: 



2(x)=x^2+1

We move all terms to the left:

2(x)-(x^2+1)=0

We get rid of parentheses

-x^2+2x-1=0

We add all the numbers together, and all the variables

-1x^2+2x-1=0

a = -1; b = 2; c = -1;
Δ = b2-4ac
Δ = 22-4·(-1)·(-1)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{-2}{-2}=1$

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